19:00:27Shinmeratwo "inputs" getting the same colouring is perfectly valid according to the colouring problem, but in my case it's not because having the same buffer for two distinct inputs makes no sense.
19:02:49ShinmeraI think I can avoid this by making every input node also form implicit connections between each of its connected ports
19:03:18ShinmeraNot sure what I should call that algorithm then, though, since it definitely isn't colouring anymore, at least not in its verbatim sense
19:12:22ShinmeraI guess in general for each port I would have to add edges between each of the other ports its connected to... Hm.
19:12:37ShinmeraWould that make it correct and not overly eager?