11:26:41PPHello. How do I do `(dotimes (i 10) (dotimes (j 10) (print (cons i j))))` equivalent in loop? I mean `(loop for i upto 10 for j upto 10` goes in parallel so to speak and doesn't give permutations
16:17:53Inlineunderstanding the machinery is a thing but modeling your domain is another thing....
16:18:50Inlinethere are so many variation possibilities....it's kinda parametric
16:19:03Inlinehard to get my head around, how to start etc....
16:19:45pnpgoodbye OOP... someone thinks it's old style
16:20:13Josh_2Theres a digital copy that I have but It's not very good quality, looks like someone did a bad job scanning the book into a digital format